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Answer to Question #62046 in General Chemistry for Matthew
Question #62046
Calculate the pH of a 0.55 M solution of C2H5NH3Cl (Kb for C2H5NH2 = 5.6 x 10-4). Record your pH value to 2 decimal places.
Expert's answer
pH = 7 - ½pKb +½lgCb
pH = 7 – ½ * (-lg [5.6 ˣ 10-4]) + ½ * lg 0.55
pH = 5.24
pH = 7 – ½ * (-lg [5.6 ˣ 10-4]) + ½ * lg 0.55
pH = 5.24
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