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Answer to Question #55851 in General Chemistry for Caitlin
Question #55851
How many grams of F are in 415 g of CaF2?
Expert's answer
M (Ca) = 40.1
M (2 F) = 38.0
M = 78.1
%F = 38/78.1
%F = 48.7
m(F) = 0.487 * 415 = 202.1
Answer: 202.1
M (2 F) = 38.0
M = 78.1
%F = 38/78.1
%F = 48.7
m(F) = 0.487 * 415 = 202.1
Answer: 202.1
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