Question

0.1 liter of NH3 is put in 0.2 liter O2 to form NO and water.
a) write the chemical equation of the reaction.
b) find if their is excess of one reagaint and calculate the excess volume.

Answer 1

Answer to Question #53038 – Chemistry – General chemistry

a) $4\mathrm{NH}_3 + 5\mathrm{O}_2 \rightarrow 4\mathrm{NO} + 6\mathrm{H}_2\mathrm{O}$

b) As you can see from equation to combust 4 L of $\mathrm{NH}_3$ you need 5 liters of $\mathrm{O}_2$. So to combust 0.1 L of $\mathrm{NH}_3$:

$$V_{O_2} = \frac{0.1 \cdot 5}{4} = 0.125 \, \mathrm{L}$$

So $\mathrm{O}_2$ is in excess.

Excess volume is:

$$\Delta V = 0.2 \, \mathrm{L} - 0.125 \, \mathrm{L} = 0.075 \, \mathrm{L}$$

Answer: excess volume of $\mathrm{O}_2$ is 0.075 L.

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