2 AlBr3 + 3 Cl2 → 2 AlCl3 + 3 Br2
If a reaction occurs using 3.75 moles AlBr3, how many moles of Br2 would be produced?
2AlBr3 + 3Cl2 = 2AlCl3 + 3Br2
According to the above reaction, 3mol Br2 is formed when 2mol AlBr3 is used.
Now we find how many moles of Br2 are formed from 3.75 moles of AlBr3.
2mol AlBr3 —— 3 mol Br2
3.75mol AlBr3 —— x mol Br2
x = 3.75 * 3 / 2 = 5.625 mol
Answer: 5.625 mol Br2
Comments
Leave a comment