Question

2 AlBr₃ + 3 Cl₂ → 2 AlCl₃ + 3 Br₂

If a reaction occurs using 3.75 moles AlBr₃, how many moles of Br₂ would be produced? 

Answer 1

2AlBr₃ + 3Cl₂ = 2AlCl₃ + 3Br₂

According to the above reaction, 3mol Br₂ is formed when 2mol AlBr₃ is used.

Now we find how many moles of Br₂ are formed from 3.75 moles of AlBr₃.

2mol AlBr₃ —— 3 mol Br₂

3.75mol AlBr₃ —— x mol Br₂

x = 3.75 * 3 / 2 = 5.625 mol

Answer: 5.625 mol Br₂