what volume (in mL) of 18.0M H2SO4 is needed to contain 2.45g H2SO4
1. Using the formula n = m / M , we find the substance quantity (n) of 2.45 g h2so4. M is the molar mass of H2SO4 .
n=m/M= 2.45/98=0.025 mol
2. From the formula CM= n /Vwe derive the formula for finding V: V = n / CM
V=n/CM = 0.025/18= 0.001388889 litr
To find the milliliter, multiply the liter by 1000: 0.001388889*1000=1.38889 ml ≈ 1.4 ml
ANSWER: 1.388889 ml or approx 1.4 ml
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