Answer to Question #339543 in General Chemistry for cccxx

Question

At 30.0 K, a container has an unknown pressure. What is the new temperature if the pressure is decreased to 33% of the original?

Answer 1

Given:

P₁ = P

T₁ = 30.0 K

V₁ = V₂ = constant

P₂ = 0.33 P

T₂ = unknown

Solution:

Since the volume and amount of gas remain unchanged, Gay-Lussac's law can be used.

Gay-Lussac's law can be expressed as: P_1 / T₁ = P_2 / T₂

P₁T₂ = P₂T₁

To find the new temperature, solve the equation for T₂:

T₂ = P₂T_1 / P₁

T₂ = (0.33 P × 30.0) / (P) = 9.9

T₂ = 9.9 K

Answer: The new temperature is 9.9 K