Question

An acid solution contains 18 kg of water and pure hydrochloric acid (HCl) , Its concentration is 0.60 mol/kg of solvent. Compute for the number of moles of solute contained in the solution.

Answer 1

Solution:

Moles of solute = Mass of solvent × Concentration

Moles of HCl = (18 kg H₂O) × (0.60 mol HCl / 1 kg H₂O) = 10.8 mol HCl

Moles of HCl = 10.8 mol

Answer: 10.8 moles of solute (HCl)