If it takes 640 J of heat energy to increase the temperature of 100 g of a substance by 25˚C (without changing its phase), calculate the specific heat of the substance.
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Expert's answer
2022-05-06T05:41:03-0400
Q = mCΔT
C = Q/mΔT
ΔT = 25˚C = 298 K
C = (640 J * 1000 )/ (100 g * 298 K) = 21.48 kJ / g*K
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