Question

A piece of metal, weighing 59.047, was heated to 100.0 degrees C. The metal was paced into a coffee cup calorimeter containing 100.0mL of water (initially at 23.7 degree C). the metal and water were allowed to come to an equilibrium temp, determined to be 27.8 degree C. Assuming no heat was lost to the surroundings, calculate the specific heat of the metal.

1)calculate the hat absorbed by the water

2)calculate the specific heat of the metal

Answer 1

heat gained = heat lost

q_metal = q_water

the specific heat of the metal is 0.402 J/g•°C