Question

A confined quantity of gas is at a pressure of 2.50 atm and a temperature of -10°C, what is the pressure if the temperature is increased to 22°C

Answer 1

The process described is called an isochoric process or constant-volume process. It can be characterized by the following equation:

$P/T = const$

That means:

$P_1/T_1 = P_2/T_2$ , where 1,2 -- states before and after temperature increase and temperature is expressed in K.

Find P₂:

$P_2 = P_1 * T_2 / T_1 = 2.5 * 295/263 = 2.80 (atm)$

Answer: 2.80 atm is the pressure of the gas after its temperature was increased.