How much heat (in joules) is used to heat a 39.79 gram sample of iron from 9.23 degrees Celcius to 100.00 degrees Celcius if the specific heat of Fe is 0.450 j/g*C? Record your answer to 2 decimal spaces.
H = mc∆x where
M = mass
C = SHC
∆x = change in temperature
H = 39.79*0.450*(100-9.23)
H = 1625.282235J = 1625.28J (2 d.p)
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