Answer to Question #324517 in General Chemistry for Ivan Ackerman

Question

Consider the neutralization reaction

2HNO3(aq)+Ba(OH)2(aq)⟶2H2O(l)+Ba(NO3)2(aq)

A  0.110 L sample of an unknown HNO3 solution required 51.1 mL of 0.150 M Ba(OH)2 of

0.150 M Ba(OH)2 for complete neutralization. What is the concentration of the 

HNO3 solution?

Answer 1

2HNO₃(aq) + Ba(OH)₂(aq) ⟶ 2H₂O(l) + Ba(NO₃)₂(aq)

n(Ba(OH)₂) = C(sol) × V(sol) = 0.150 mol/L × 0.0511 L = 0.007665 mol

2 mol HNO₃ - 1 mol Ba(OH)₂

x mol HNO₃ - 0.007665 mol Ba(OH)₂

x = 0.007665 × 2 = 0.01533 mol

C(sol) = n(HNO₃) / V(sol) = 0.01533 mol / 0.110 L = 0.139 mol/L