A 0.477 mol sample of O_{2} gas has a volume of 10.9 L at a certain temperature and pressureIf all this O_{2} were converted to ozone (O_{3}) at the same temperature and pressure, what is the ozone volume (in liters)? 3O 2 (g) 2O 3 (g)
So the first part of the question is regarding the oxygen and ozone and the volume of it. So three moles of 02 days give. That is two moles of oh three. So we can say that three liter of or two will give two liter of 03. So what will 12.2 liters give? So we can say that the volume of oh three will be equal to 12.2, multiplied by two divided by three. So the volume of 43 will come out to be 8.13 liters. So this is the answer for the volume of ozone. Moving on to the next part. That is the same volume as 22.4 liter at STP. So we'll calculate the moles. So for a the number of moles will be equal to 12.1 by 12.1 that is one mole similarly. 2nd case the number of moles will be 6.04 16.04. Bye. The Molar Mass 16.04. So again, this is one mole K. C. That is at cl 36.46 g is given. And the molar mass is also 36.46. This will also be one bullet Ksd regarding CH three. Oh it's the number of moles. So the given mass is 32.5 and the molar mass is 32.5. So again this is one mole and the last case will right down over here that is moles of C. 02. So that given weight is 20 to 1 molar masses 44. This is 0.5 moles. Now, at STP one mole Is equal to 22.4 L. So we can say that a BCD are the correct answers. Thank you.
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