Question

What is the concentration of 22.50 mL of NaOH if this was neutralized with 20.00 mL of 0.120 M HCI in the following reaction? NaOH +HCI. NaCI+H2O

Answer 1

$NaOH+HCl \rightarrow NaCl + H_2O$

n(HCl)=0.12x0.02=0.0024 mole

n(HCl)=n(NaOH)=0.0024 mole

c(NaOH)=0.0024/0.0225=0.107 M