Question

FOR EXAMPLE:

C₃H₆O + 4O₂ → 3CO₂ + 3H₂O ∆H=-1790kJ

Using 1 mole of C₃H₆O: -1790kJ

Using 2 moles of C₃H₆O: 2(-1790kJ)

Consider the information above on the combustion of acetone. Solve

the following problem involving the Enthalpy of Chemical Reactions. Show yours solutions. You may refer to the lecture notes for sample problems.

Calculate the amount of heat released during the combustion of

a. 0.75 mole of C3H6O

b. 120g of C3H6O

Answer 1

a. If 1 mole of C3H6O: -1790kJ

(075/ 1)× -1790= -1342.5 kJ

b. 120g of C3H6O

Moles= 120/58= 2.07 moles

Heat = 2.07 × -1790= - 3703.45 kJ