at what Kekvin temperature will 37.5 mol of Ar occupy a volume of 725 L at a pressure of 675 torr ?
At STP ie 760 torr and 273K, 1 mol occupy 22.4L.
Therefore, 37.5 mol occupy 22.4×37.5= 840L
P1= 760 torr, V1= 840L and T1= 273K
P2= 675 torr, V2= 725L and T2= ?
P1V1÷T1 = P2V2÷T2
T2= P2V2T1 ÷(P1V1)
= (675×725×273)÷(760×840)
= 209.3K
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