2 Pb(NO3)2 --> 2 PbO + 4 NO2 + O2
How many grams of lead (II) oxide are produced to form 5 grams of oxygen?
How many grams of lead (II) nitrate are needed to make 7 moles of nitrogen dioxide
How many moles of oxygen can be made from 14 moles of lead (II) nitrate?
The given thermal decomposition reaction can be shown as follows
"2Pb(NO_3)_2 \\longrightarrow2PbO+4NO_2+O_2"
from above reaction we can say that 2 mole of lead nitrate gives 2 mole of lead oxide, 4 mole of nitrogen dioxide and 1 mole of oxygen
(a)
mole of oxygen produced = "\\frac{5}{32}=0.15625"
mole of lead oxide produced = "2 \\times 0.15625= 0.3125"
mass of lead oxide = "223.2\\times 0.3125 = 69.75 g"
(b) 4 mole of nitrogen dioxide produced from 2 mole of lead oxide
7 mole of dinitrogen produced from = "\\frac{2}{4}\\times 7 = 3.5" lead nitrate required
Mass of lead nitrate = 1159.2 g
(c) 2 mole of leadnitrate gives 1 mole of dioxygen
Now, 14 mole of lead nitrat gives 7 mole of dioxygen
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