Answer to Question #316943 in General Chemistry for chan

Question

How many ml of 1.2 M H2SO4 are required to neutralize 25.0 ml of 1.5 M NaOH?

Answer 1

Solution:

Balanced chemical equation:

H₂SO₄ + 2NaOH ⟶ Na₂SO₄ + 2H₂O

According to stoichiometry:

Moles of H₂SO₄ = Moles of NaOH / 2

or:

2 × Molarity of H₂SO₄ × Volume of H₂SO₄ = Molarity of NaOH × Volume of NaOH

Therefore,

Volume of H₂SO₄ = (Molarity of NaOH × Volume of NaOH) / (2 × Molarity of H₂SO₄)

Volume of H₂SO₄ = (1.5 M × 25.0 ml) / (2 × 1.2 M) = 15.625 mL = 15.6 mL

Volume of H₂SO₄ = 15.6 mL

Answer: 15.6 ml of H₂SO₄ are required