Answer to Question #304422 in General Chemistry for Del

Question

Consider the following reaction:

2 NO + 2 H₂ → N₂ + 2 H₂O

a.   The rate law for this reaction is first order in H₂ and second order NO. Write the rate law.

b.   If the rate constant for this reaction at 1000 Kelvin is 6.0 x 10⁴ M ^-2 s^-1, What is the reaction rate when [NO] = 0.025 M and [H₂] = 0.015 M?

Answer 1

2NO + 2Н₂ → N₂ + 2H₂O

a. R = k[NO]²[H₂]¹

b. R = 6.0 x 10⁴ M^-2s^-1 x (0.025 M)² x (0.015 M) = 0.5625 M/s