Answer to Question #304326 in General Chemistry for Prince simuchimba

Question

If 4.58 x 104

g CH3OH is actually produced, what is the percent yield of methanol

Answer 1

Here The Reaction is missing and the amount of reactant is also missing.

Suppose

CO + 2H2 = CH3OH

28 gm of CO reacts with 4 gm of H produces 32 gm of CH3OH

Now from the amount of reactants the amount of CH3OH should be produced need to be calculated.

If this value is X.

Percentage of yield = (X/ (4.58 × 104)) × 100%