Question #300665

Calculate the number of moles of oxygen present in 2.0g of Na3PO4

1
Expert's answer
2022-02-22T15:43:03-0500

Molar mass of Na3PO4=164gNa_3PO_4=164g

Moles of Na3PO4=2164Na_3PO_4= \frac{2}{164}



Moles of oxygen atoms

4×2164=0.04878moles4×\frac{2}{164}=0.04878 moles





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