using conversion method, calculate the molality and molarity of aqueous phosphoric acid solution 1.88 gram/ml containing 20% by mass of h3 po4? h=1 p=31,o=16
Molality= moles of solute/ kg of solvent
Moles= 1880/98= 19.18moles
Molality= 19.18 mol/ kg
Molarity= moles/ litre
Molarity= 19.18M
Comments
Leave a comment