How many grams of Fe2O3 forma 200 grams of Fe?
Write the balanced equation for the reaction taking place:
4Fe+3O2→2Fe2O34Fe+3O_2\to2Fe_2O_34Fe+3O2→2Fe2O3
200gFe×1molFe55.85g×2molFe2O34×160g/molFe2O3=286.48gFe2O3200gFe×\frac{1molFe}{55.85g}×\frac{2molFe_2O_3}{4}×160g/molFe_2O_3 =286.48g Fe_2O_3200gFe×55.85g1molFe×42molFe2O3×160g/molFe2O3=286.48gFe2O3
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