Answer to Question #298402 in General Chemistry for Mae

Question

When 10.0 g KOH is dissolved in 100.0 g of water in a coffee-cup calorimeter, the temperature rises from 25.18 0C to 47.53 0C. What is the enthalpy change in kJ per mole of KOH dissolved in the water? The specific heat capacity of water is 4.184 J/g0C

Answer 1

$H= mc\Delta T$

$H=100×4.184×(47.53-25.18)=9351.24J$

Molar mass of KOH= 56g/mol

Molar enthalpy change

$\frac{56}{10}×9351.2=52.37kJ$