Answer to Question #296148 in General Chemistry for cols

Question

Phosphoric acid (H_{3}*P * O_{4}) can be prepared from phosphorus triiodide (P*l_{3}) according to the reaction:

PI 3 (s)+H 2 O(l) H 3 PO 4 (aq)+HI(g)

Balance the equation. If 150 grams of Pl_3 ( MM=411.7 g/mol) is added to 250 milliliters og H 2 O(MM=18.01 g / mol , rho=1.00 g mL ) identify the limiting and excess reagents. How many grams of H3PO4 (MM=97.99 g / mol ) will be theoretically produced?

Answer 1

To get the mass of water

Density= mass/vol

Mass=vol×density

Mass=250g

If 411g of Pb react with 54g of H2O

Then 150g ------------------------- Xg of H2O

X=19.71g

So H2O is the excess reagent and PI is the limiting reagent.

2)If 411.7g of PI3 produce 97.99g of H3PO4

Then 150g will produce Xg of H3PO4

X=35.7g of H3PO4 will be produced.