how many grams of lactose must be added to 655 grams of water in order to prepare a solution with a percent mass concentration of 10%?
Let m === The mass of lactose
m655+m=10100\frac{m}{655+m}=\frac{10}{100}655+mm=10010
100m=6550+10m100m=6550+10m100m=6550+10m
90m=655090m=655090m=6550
m=72.78gm=72.78gm=72.78g
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