Directions. Solve the following problems. Show your solutions.
I. For the voltaic cell, 2 Na(s) + Fe2+(aq) → 2 Na+
(aq) + Fe(s)
a) Write the two half-reactions.
b) Write the cell notation.
c) Calculate E ° for the cell.
II. Consider the fission reaction 1
0n + 235
92U →
89
37Rb + 3 0
-1e + 3 1
0n + 144
58Ce
How much energy in kilojoules is released per gram of Uranium- 235?
III. For Al-28, calculate the binding energy in kilojoules /mol?
IV. Sketch a portion of the acrylonitrile polymer ( Refer to Table 23.1) assuming it is a
a) head-to-tail polymer
b) head-to-tail, tail-to-tail polymer
To determine the E? value of a cell, we determine the anode and cathode half cell reactions and then calculate the E? by the help of the formula:
E ? ( cell ) = E? (cathode) - E? (anode)
The half-cell reactions are written as below:
Anode: Na(s) → Na+ (aq) + e- E? (anode) = -2.714V
Cathode: Fe2+ (aq) + 2e- → Fe(s) E? (cathode) = -0.409V
So, E? (cell) = -0.409 – (-2.714) = 2.305V
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