For the reaction attached below. What are the values of the equilibrium constants (Kp and Kc) if the pressure of CO2 is 0.384 atm at 500 degrees Celsius?
Kp=Kc(RT)ΔnKp = Kc (RT)ΔnKp=Kc(RT)Δn
PV = nRT
0.384× v= 8.314× 773.15
V = 16739.5
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments