Question

Consider the reaction attached below. If the partial pressure of N2, H2, and NH3 are 1.3 atm, 0.83 atm, and 0.85 atm respectively, what is the equilibrium constant of the reaction in terms of partial pressure of the gases?

Answer 1

$N_2+3H_2\rightleftharpoons2NH_3$

$K_p=\frac{0.85^2}{1.3×0.83^3}=0.972$