Mg(OH)2 + HCl → MgCl2 + H2O
Determine the number of moles of magnesium chloride produced when 5.0 mol of HCl is combined with excess Mg(OH)2
Balanced equation would be;
Mg(OH)2 + 2HCl - MgCl2 + 2H2O
for every two moles of HCl reacting, one mile of MgCl2 is a product.
Therefore if 5moles of HCl is used 2.5 moles of MgCl2 is produced.
= 2.5 moles of MgCl2
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