Question #281654

A 100 gram sample of a mixture was known to contain calcium carbonate and something else, if the sample was reported to contain 45% calcium which of the following could be the other substance in the mixture?

A) NaCl

B) CaO

C) CaI2

D) Na2CO3


I know the answer is B but I don't know how they got that answer. I need someone to show me how they work it out.


Expert's answer

The remaining percentage is 100%-45%=55% which is almost equal to percentage mass of CaO=56/100×100=56%=56/100\times 100=56\%

So the other substance is CaO


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