A gas sample occupies a volume of 15.0 L at 30 oC and 750 torr. At what temperature will this gas occupy a volume of 25.0 L at the same pressure?
volume V1 =12.0 L
temperature T1 = 25°C = 273 K
and Pressure = 750 torr.
new volume V2 =15.0 L at 750 torr
temperature T2 = ?
combined gas law says
V1/T1 = V2/T2
T2 = V2 * T1/V1 = 15 L * 273 K/12 L = 341.25 K
Answer
Final temperature = 341 K
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