Question

A student weighs out a 1.91 g sample of NH4CH3COO , transfers it to a 100. mL volumetric flask, adds enough water to dissolve it and then adds water to the 100. mL tick mark.

What is the molarity of ammonium acetate in the resulting solution?

Answer 1

Molar mass of Ammonium acetate $=77.0825g/mol$

Number of moles in $100ml$ solution $=\frac{1.91}{77.0825}$

Molarity $=\frac{1000}{100}×\frac{1.91}{77.0825}=0 .2478M$