Question

If the theoretical yield of the reaction is equal to 267.0 grams of AlBr3, what is the percent yield of the reaction if the actual yield is 250.0 grams of AlBr3?

Answer 1

$\to$

Percent $$yield=(Actual yield/Theoretical yield)×100%

Percent Yield $=\frac{250}{267}×100=93.63$ %