Calculate the theoretical yield of aluminum chloride (in grams) that can be produced from 10.00 grams of aluminum metal.
Al=26.982=26.982=26.982
Cl=35.453=35.453=35.453
Al Cl3=133.34=133.34=133.34
2Al +3+3+3 Cl2 →2\to2→2Al Cl3
Log of Aluminium =1026.982=0.3706moles=\frac{10}{26.982}=0.3706moles=26.98210=0.3706moles
Mole ratio === Al ::: Al Cl3
=1:1=1:1=1:1
Moles of Al Cl3 =0.3706moles=0.3706moles=0.3706moles
Mass =0.3706×133.34=0.3706×133.34=0.3706×133.34
=49.418g=49.418g=49.418g
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