When cadmium metal reduces Cu2+ in solution, Cd2+ forms in addition to copper metal. Given that ΔG° = −143 kJ/mol, calculate K at 25°C. What is E°CELL of a voltaic cell that uses this reaction?
Cd(s) + Cu^2+(aq) = Cd^2+(aq) + Cu(s)
Cu2++2e---->> Cu. E° = +0.39V
Cd2++2e-----> Cd E° = -0.14V
Comments
Leave a comment