Answer to Question #269356 in General Chemistry for leo

Question

A solution of glycerol, C3H5(OH)3, in 735 g of water has a boiling point of 104.4 °C at a

pressure of 760 mm Hg. What is the mass of glycerol in the solution? What is the

mole fraction of the solute?

Answer 1

We know that

ΔTb = Kb x m

Where ΔTb = elevation in boiling point = boling point of solution - boiling point of water

$=104.4-100=4.4°C$

Msolute $=4.4×735=3234$