How many moles of NH₃ can be produced from 4.71 moles of nitrogen in the following reaction:
N₂ (g) + 3 H₂ (g) → 2 NH₃ (g)
Mole ratio = 1 : 2
Moles of NH3=2×4.71=9.42molesNH_3=2×4.71=9.42molesNH3=2×4.71=9.42moles
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