Answer to Question #268555 in General Chemistry for grizz

Question

If 10.0 moles of O₂ are reacted with excess NO in the reaction below, and only 3.8 mol of NO₂ were collected, then what is the percent yield for the reaction?

2 NO (g) + O₂ (g) → 2 NO₂ (g)

Answer 1

Calculation of theoretical yield:

n(NO₂) = 2n(O₂) = 20 mol

Proportion:

20 mol – 100 %

3.8mol – x

$x = \frac{3.8\times 100}{20} = 19$ %

Answer is 19 %