Question #268294

At constant temperature, a sample of helium gas expands from 922 mL to 1.14 L against a pressure of 2.33 atm. Find w (in J) done by the gas (1J = 9.87310 expoent -3 atm L).


1
Expert's answer
2021-11-19T11:53:01-0500

922×1.14×2.33/9.8731= 248.05J


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