Answer to Question #268294 in General Chemistry for nyah

Question #268294

At constant temperature, a sample of helium gas expands from 922 mL to 1.14 L against a pressure of 2.33 atm. Find w (in J) done by the gas (1J = 9.87310 expoent -3 atm L).

Expert's answer

922×1.14×2.33/9.8731= 248.05J

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