Answer to Question #267958 in General Chemistry for maggie

Question

Consider the reaction of solid aluminum iodide and potassium metal to form solid potassium iodide and aluminum metal.

The balanced chemical equation is AlI₃(s) + 3 K(s) → 3 KI(s) + Al(s). What quantity in moles of aluminum are produced if 3.05 moles of aluminum iodide are reacted with 7.31 moles of potassium based on the balanced chemical equation?

Answer 1

The reaction equation is;

AlI₃ + 3_K $\implies$ 3KI + Al

The ratio of reaction is ;

1:3:3:1

Respectively

3.05 moles of AlI3 is in excess so the limiting mole is 7.31

The moles therefore= 7.31÷3

Answer = 2.437moles of Aluminium