Determine the empirical and molecular formula of a compound composed of 18.24 g Carbon, 0.51 g Hydrogen, and 16.91 g Fluorine has a molar mass 562.0 g/mol.
Element
Mass
Molecular mass
Moles
Mole ratio
C=3 H=1 F=7/4
C=12 H=4 F=7
Empirical formula =C12H4H7
Empirical formula mass=(12*12)+ (4*1) + (7*19)=281
Mass formula=562
Therefore, mass formula /empirical formula=562÷281=2
Compound formula =C24H8F14
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