Question

Determine the empirical and molecular formula of a compound composed of 18.24 g Carbon, 0.51 g Hydrogen, and 16.91 g Fluorine has a molar mass 562.0 g/mol.

Answer 1

Element

1. Carbon
2. Hydrogen
3. Flourine

Mass

1. 18.24
2. 0.51
3. 16.91

Molecular mass

1. 12
2. 1
3. 18.998

Moles 

1. (18.24÷12)=1.52
2. (0.51÷1)=0.51
3. (16.91 ÷18.998) =0.890

Mole ratio

1. (1.52÷0.51)=3
2. (0.51÷0.51)=1
3. (0.89 ÷0.51) =1.75 =7/4

C=3 H=1 F=7/4

C=12 H=4 F=7

Empirical formula =C12H4H7

Empirical formula mass=(12*12)+ (4*1) + (7*19)=281

Mass formula=562

Therefore, mass formula /empirical formula=562÷281=2

Compound formula =C₂₄H₈F₁₄