Answer to Question #266957 in General Chemistry for kkk

Question

What mass ofPCl

5

P

C

l

5

 will be produced from the given masses of both reactants?

Express your answer to three significant figures and include the appropriate units.

View Available Hint(s)

Answer 1

Solution

P₄ + 10 Cl₂ = 4 PCl₅

Combination of one mole of P₄ with ten moles of chlorine gives four moles of PCl₅.

MW(P₄) = 123.895048 g mol^-1

MW(Cl₂) = 70.906 g mol^-1

MW(PCl₅) = 208.22 g mol^-1

Part B

n(P₄) = m(P₄)/MW(P₄) = 26.0 g/123.895048 g mol-1 = 0.210 mol

n(PCl₅) = 4 n(P₄) = 0.839 mol

Part C

N(Cl₂) = m(Cl₂)/MW(Cl₂) = 59.0 g/70.906 g mol-1 = 0.832 mol

n(Cl₅) = 0.4 n(Cl₂) = 0.333 mol

Part D

Chlorine is limiting reagent. 0.333 moles of PCl₅ will be formed:

m(PCl₅) = n(PCl₅)*MW(PCl₅) = 0.333 mol * 208.22 g mol^-1 = 69.3 g