Question

If 3.4 moles of sulfur dioxide reacts with excess oxygen gas, how many moles of sulfur trioxide will form?

Answer 1

The equation is below:

2SO₂ + O₂ --> 2SO₃

According to the equation, 2 moles of sulfur dioxide produce 2 moles of sulfur trioxide. Therefore,

$n(SO_3)=3.4\ mol(SO_2)\times\frac{2\ mol(SO_3)}{2\ mol(SO_2)}=3.4\ mol$

Answer: 3.4 moles