If 3.4 moles of sulfur dioxide reacts with excess oxygen gas, how many moles of sulfur trioxide will form?
The equation is below:
2SO2 + O2 --> 2SO3
According to the equation, 2 moles of sulfur dioxide produce 2 moles of sulfur trioxide. Therefore,
"n(SO_3)=3.4\\ mol(SO_2)\\times\\frac{2\\ mol(SO_3)}{2\\ mol(SO_2)}=3.4\\ mol"
Answer: 3.4 moles
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