How many grams of chlorine are required to react completely with 5.00 moles of sodium to produce sodium chloride? 2Na + Cl2 => 2NaCl
2Na+Cl2→2NaCl2Na+Cl_2\to 2NaCl2Na+Cl2→2NaCl
Mole ratio, sodium: chlorine = 2:1
molesmolesmoles of chlorine =5/2=2.5moles5/2=2.5moles5/2=2.5moles
mass of chlorine required =70.90×2.5=177.25g=70.90\times 2.5=177.25g=70.90×2.5=177.25g
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