Answer to Question #264915 in General Chemistry for Kyle

Question

What volume of hydrogen will be produced at stp by the reaction 55.5 grams of magnesium with excess water according to the following reaction

Answer 1

Mg + 2H₂O $\rightarrow$ Mg(OH)₂ + H₂

moles of Mg taken = (67.3/24) = 2.80 moles

Moles of H₂ produce = 2.80moles

volume of H₂ at STP = 2.80× 22.4 L = 62.8 L