Answer to Question #264872 in General Chemistry for jay

Question

Given the equation,

Mg(OH)2 + 2 HCl → MgCl2 + 2 H2O

Assume that a person takes 0.100 g Mg(OH)2. How many mol of MgCl2 will be produced from the ingested antacid, assuming all of the antacids undergo the reaction?

Answer 1

M(Mg(OH)₂) = 58.32 g/mol

n(Mg(OH)₂) $= \frac{0.100}{58.32} = 0.001714 \;mol$

According to the reaction:

n(MgCl₂) = n(Mg(OH)₂) = 0.001714 mol

Answer: 0.001714 mol