How many grams of hydrogen gas are needed to produce 10 000.0 g of ammonia
N2 + 3H2 → 2NH3
Calculate moles of NH3 in 10000.0g
Moles=10000.017.031=571.16molesMoles=\frac{10000.0}{17.031}=571.16molesMoles=17.03110000.0=571.16moles
Moles of hydrogen =32×571.16=856.74moles=\frac{3}{2}×571.16=856.74moles=23×571.16=856.74moles
Mass of hydrogen =856.74×1.00784=863.46grams=856.74×1.00784=863.46grams=856.74×1.00784=863.46grams
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