Answer to Question #264584 in General Chemistry for nannon

Question

4Er+3O2->2Er2O3

how many gram of Er must be reacted with O2 to produce 28.78gEr2O3?

Answer 1

M(Er₂O₃) = 382.56 g/mol

n(Er₂O₃) $= \frac{28.78}{382.56} = 0.075 \;mol$

According to the reaction:

n(Er) = 2n(Er₂O₃) $= 2 \times 0.075 = 0.150 \;mol$

M(Er) = 167.26 g/mol

m(Er) $= 0.150 \times 167.26 = 25.16 \;g$

Answer: 25.16 g