What mass of chromium metal is in a sample that contains 6.9 × 1025 formula units of ammonium dichromate, (NH4)2Cr2O7(s)?
Moles of (NH4)2Cr2O7=6.9×10256.022×1023=114.57moles(NH_4)_2Cr_2O_7=\frac{6.9\times 10^{25}}{6.022\times 10^{23}}=114.57 moles(NH4)2Cr2O7=6.022×10236.9×1025=114.57moles
Moles of Cr =2×114.57=229.15moles=2\times 114.57=229.15moles=2×114.57=229.15moles
Mass of Cr=229.16mol×51.99g/mol=1.2×104g=229.16mol \times 51.99g/mol=1.2\times 10^4 g=229.16mol×51.99g/mol=1.2×104g
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